Question

two adjacent sides of rectangle are (3x²-5y²) and (6x²-4y) find it's perimeter​

Answer 1

Answer:

$perimeter = 2(l + b) \\ = 2(3x {}^{2} - 5y {}^{2} + 6x {}^{2} - 4y) \\ = 2(9x {}^{2} - 5y {}^{2} - 4y) \\ = 18 {x}^{2} - 10 {y}^{2} - 8y$

Answer 2

★ Solution ↓

We know that :-

Perimeter = 2(Length + Breadth)

Perimeter = 2(3x² - 5y² + 6x² - 4y)

Perimeter = 2(3x² + 6x² - 5y² - 4y)

Perimeter = 2(9x² - 5y² - 4y)

Perimeter = 18x² + 10y² - 8y (Ans)

Therefore,

perimeter of rectangle = 18x² + 10y² - 8y