Question

Two aeroplanes bomb a target in succession. The probability of each correctly scoring a hit is 0.3 and 0.2
respectively. The scores will bomb only if the misses the target. Find the probability that the target is hit by
second plane
%​

Answer 1

Answer:

Answer

Given: The probability of aeroplane I hitting correctly, P(A)=0.3, the probability of aeroplane II hitting correctly, P(B)=0.2

To find: the probability that the target is hit by the second plane

Sol: Probability of Aeroplane I hitting the target in first turn= P(A)

The probability of aeroplane II hitting the target in the first turn = P(

A

)×P(B)

Hence, the probability that the target is hit by the second plane =

P(

A

)×P(B)+P(

A

)×P(

B

)×P(

A

)×P(B)+...

⟹=0.7×0.2+0.7×0.8×0.7×0.2+...

⟹=0.14[1+0.56+0.56×2+...]

this is an geometric progression.

So the required probability becomes

0.14[

1−0.56

1

]

⟹=0.312=

22

7

Step-by-step explanation:

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