Two aeroplanes leaves an airport, one after the another.
ater moving on a unaway, one flies due north and other
files due south. The speed of two aeroplanes is 400km/hr
and 500 km/he respectively considering PQ as cuncury and
A and B are any two points in the paths followed by two
Planes. then answer the following questions.
please answer the questions in the attached picture please answer fast
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Answers
Answer:
I will give answer and I do this in Marathi and will give this in English translating ok and mark me as brand list please and you this in Marathi will solve it into
The first aeroplane leaves an airport and flies due north at a speed of 1000 km per hr.
∴ Distance travelled in 1.5 hrs.
=1000×1.5=1500 km
Similarly, Distance traveled by second aeroplane,
=1200×1.5=1800 km
In △ABC,
BC is distance travelled by first aeroplane and BA is the distance traveled by second aeroplane.
Hence, applying Pythagoras Theorem,
1) tan = perpendicular / base
= 1.2 / 1.6 = 3 / 4
2) cot = 3000 / 1600 = 15 / 8
3) tan = 1600 / 1200 = 4 / 3
4) sec = 2000 / 1200 = 5 / 3 ( 2000 = PA )
5) cosec = 1600 / 3400 = 8 / 17 ( 3400 = PB )
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