Question

Two alloys a and b are composed of two basic elements the ratio of the composition of the two basic elements in the two hello sir 5 is to 3 and 1 is to 2 respectively in u l o x is formed by mixing the two alloys a and b in the ratio 4 is to 3 what is the ratio of the composition of the two basic elements in array x

Answer 1

When you need to find the average, it is better to use the formula in its original form: Avg = (C1*w1 + C2*w2)/(w1 + w2)

Avg = [(5/8)*4 + (1/3)*3]/(4+3) = 1/2

Ratio of the 2 elements in the mixture = 1:1

Obviously the formula will work in the other form too though it is best to use that when you need to find the ratio of the weights. Using the formula in the other form: w1/w2 = (A2 - Aavg)/(Aavg - A1)

element 1 in A = 5/8

element 1 in B = 1/3

element 1 in mixture = x

4/3 = (1/3 - x) / (x - 5/8)

4/3(x - 5/8) = 1/3 - x

(7/3)x = 7/6

x = 1/2

Ratio of elements in the mixture = 1:1

Answer 2

Answer:

1:1

Explanation:

Let the actual amount of A be 4x and actual amount of B be 3x since A and B are in the ratio 4/3

amount of first basic element in the new alloy T (5/8)*4x + (1/3)*3x = (7x)/2

amount of second basic element in the new alloy T (3/8)*4x + (2/3)*3x= (7x)/2

so ratio of first basic element to second basic element: [(7x)/2 ] / [ 7x/2] = 1/1 = 1:1