Two angles are complementary and one of the angles is 18° more than the other, then find the two
angles.
Answers
Answer:
Answer:Let one angle be x
Answer:Let one angle be xand another angle be x+18
Answer:Let one angle be xand another angle be x+18and the angles are complementry
Answer:Let one angle be xand another angle be x+18and the angles are complementry∠A+∠B=90
Answer:Let one angle be xand another angle be x+18and the angles are complementry∠A+∠B=90x+x+18=90
Answer:Let one angle be xand another angle be x+18and the angles are complementry∠A+∠B=90x+x+18=902x=90-18
Answer:Let one angle be xand another angle be x+18and the angles are complementry∠A+∠B=90x+x+18=902x=90-182x=72
Answer:Let one angle be xand another angle be x+18and the angles are complementry∠A+∠B=90x+x+18=902x=90-182x=72x=36
Answer:Let one angle be xand another angle be x+18and the angles are complementry∠A+∠B=90x+x+18=902x=90-182x=72x=36∠a=36
Answer:Let one angle be xand another angle be x+18and the angles are complementry∠A+∠B=90x+x+18=902x=90-182x=72x=36∠a=36∠b=36+18=54
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Answer. Sum of two complementary angles is 90°
let 1st angle be x and 2nd be 18+x...
as given in the ques.
A.T.Q. ,
x+18+x=90°
2x+18=90°
2x=90-18
2x=72°
x=72/2
x=36°
Means 1st angle = 36°
And 2nd angle = x+18
= 36+18
=54°
U can also check the answer by adding both...
36°+54°=90 °
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