Two angles of a parallelogram KLMN are in the ratio of 2:3 . Then the measure of angles are
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The measures of the Two angles is 72° and 108°.
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In the given figure,
Let ∠ADC = 2x and ∠BCD = 3x
We know that in a parallelogram, opposite sides are parallel.
⇒ AD ║ BC.
Taking DC as a transversal,
∠ADC + ∠BCD = 180° (∵ Co Interior angles sum up to 180°)
⇒ 2x + 3x = 180°
⇒ 5x = 180°
⇒ x = 180 ÷ 5
⇒ x = 36°
Since we have found out the value of x, now let us find the angles.
∠ADC = 2x = 2 × 36 = 72°
∠BCD = 3x = 3 × 36 = 108°
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