Math, asked by asranichirag01006, 6 months ago

Two angles of a parallelogram KLMN are in the ratio of 2:3 . Then the measure of angles are ​

Answers

Answered by riteshyadav9568
1

ANSWER :

The measures of the Two angles is 72° and 108°.

Attachments:
Answered by Aryan0123
1

\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1,1)(1,1)(6,1)\put(0.4,0.5){\bf D}\qbezier(1,1)(1,1)(1.6,4)\put(6.2,0.5){\bf C}\qbezier(1.6,4)(1.6,4)(6.6,4)\put(1,4){\bf A}\qbezier(6,1)(6,1)(6.6,4)\put(6.9,3.8){\bf B}\end{picture}

In the given figure,

Let ∠ADC = 2x    and    ∠BCD = 3x

We know that in a parallelogram, opposite sides are parallel.

⇒ AD ║ BC.

Taking DC as a transversal,

ADC + BCD = 180°   (∵ Co Interior angles sum up to 180°)

⇒ 2x + 3x = 180°

⇒ 5x = 180°

⇒ x = 180 ÷ 5

x = 36°

Since we have found out the value of x, now let us find the angles.

∠ADC = 2x = 2 × 36 = 72°

∠BCD = 3x = 3 × 36 = 108°

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