Question

Two angles of a
quadrilateral are 70 and
80 and the third angle is double than
the fourth angle find
two angle​

Answer 1

Answer:

The spelling of cutie is wrong.

Koi na maybe it's your typing mistake.

Dog's name = Lucy

Answer 2

Question :-

• Two angles of a quadrilateral are 70° and 80°. The third angle is double than the fourth angle. Find these two angles.

Answer :-

• The third angle is 140° and the fourth angle is 70°.

Given :-

• Two angles of a quadrilateral are 70° and 80°.
• The third angle is double than the fourth angle.

To find :-

• The two unknown angles.

Step-by-step explanation :-

Let the fourth angle be x.

Then the third angle will be 2x, because it's double than the fourth angle.

The other two angles are 70° and 80°.

We know that :-

$\underline{\boxed{\sf Sum \: of \: all \: angles \: in \: a \: quadrilateral = 360^{\circ}.}}$

So, that means all these angles must add up to 360°.

$\tt\implies x + 2x +70^{\circ} + 80^{\circ} = 360^{\circ}$

Adding 70° and 80°,

$\tt \implies x + 2x + 150^{\circ} = 360^{\circ}$

Adding x and 2x,

$\tt \implies 3x + 150^{\circ} = 360^{\circ}$

Transposing 150° from LHS to RHS, changing it's sign,

$\tt \implies3x = 360^{\circ} - 150^{\circ}$

On simplifying,

$\tt \implies3x = 210^{\circ}.$

Transposing 3 from LHS to RHS, changing it's sign,

$\tt \implies x = \dfrac{210^{\circ}}{3}$

Dividing 210° by 3,

$\tt\implies x = 70^{\circ}.$

• The value of x = 70°.

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Hence, the unknown angles are as follows :-

$\tt x = 70^{\circ}.$

$\tt2x = 2 \times 70^{\circ} = 140^{\circ}.$