two angles of a traingle are equal and third angle is greater than each of those angles by 30 . determine all the angles of the triangle
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Let equal angles be x
A/c to ques
Third angle = x+30
Now we know sum of angles = 180
x+x+x+30=180
3x=150
x= 50
So angles of ∆ are 50,50,80
A/c to ques
Third angle = x+30
Now we know sum of angles = 180
x+x+x+30=180
3x=150
x= 50
So angles of ∆ are 50,50,80
Answered by
3
The angle sum property of triangle =180
X+x+x+30=180
3x=150
x=50degre
Hope it helps you
Please mark it as the brainlest
X+x+x+30=180
3x=150
x=50degre
Hope it helps you
Please mark it as the brainlest
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