Question

two angles of a triangle are equal and the third angle is greater than each of these angles by 30 degree find the measure of all the angles of the triangle​

Answer 1

Answer:

50° , 50° , 80 °

Step-by-step explanation:

Let us take the equal angles = x

according to question,

x+x+(x+30)= 180° (angle sum property)

3x+30= 180°

3x= 180-30

x = 150/3

x= 50°

So the angles are: x= 50°

x= 50°

(x+30) = 50+30 = 80°

Answer 2

Answer:

if two angles are same than assume both of the angles as =X,

Now

some of all angles of triangle is 180.

angle A + angle B + angle C = 180

X + X + X+30 = 180

3X + 30 = 180

3X = 180-30

3X = 150

X = 150/3

X = 50

NOW

ANGLE A= X=30

ANGLE B= X = 30

ANGLE C= X+30= 30+50=80