two angles of a triangle are equal and the third angle is greater than each of these angles by 30 degree find the measure of all the angles of the triangle
Answers
Answered by
4
Answer:
50° , 50° , 80 °
Step-by-step explanation:
Let us take the equal angles = x
according to question,
x+x+(x+30)= 180° (angle sum property)
3x+30= 180°
3x= 180-30
x = 150/3
x= 50°
So the angles are: x= 50°
x= 50°
(x+30) = 50+30 = 80°
Answered by
9
Answer:
if two angles are same than assume both of the angles as =X,
Now
some of all angles of triangle is 180.
angle A + angle B + angle C = 180
X + X + X+30 = 180
3X + 30 = 180
3X = 180-30
3X = 150
X = 150/3
X = 50
NOW
ANGLE A= X=30
ANGLE B= X = 30
ANGLE C= X+30= 30+50=80
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