Question

Two angles of a triangle are equal and the third angle is greater than each one of them by 18. find the angles

Answer 1

x+x+x+18=180
3x=168
x=59

Answer 2

Answer:

I hope this resolves your query.

Step-by-step explanation:

Let two equal angles of a triangle be x°

and third angle = (x+18)°

According to question

x+x+x+18 = 180

=> 3x+18 = 180

=> 3x = 180 - 18

=> x = 162

=> x = 162/3

so, x = 54

So, first angles = 54°.

other angle = 54°.

and third angle = 54+18

= 72°.