Two angles of a triangle are equal and the third angle is greater than each of these angles by 30 find all the angle of the triangle
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let the equal angles be x nd the the third angle be 30+x
then,
x +x + (x+30)=180. (bcoz angle sum property)
3x +30 =180
3x= 150
x= 50
hence the angles are
50,50 and 80
then,
x +x + (x+30)=180. (bcoz angle sum property)
3x +30 =180
3x= 150
x= 50
hence the angles are
50,50 and 80
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