Math, asked by chouhanrahil48, 1 year ago

Two angles of a triangle are equal and third angle is greater than each of those angles by 30° , determine all the angles of the triangle

Answers

Answered by ruthvikrp853
3

Answer:

50,50,80

Step-by-step explanation:

Let all angle be x,y and z

So x=y

And x+30=y+30=z

we will get x+x+x+30=180 (angle sum property of triangle)

3x=150

x=50

Y=50

And z=x+30=80

So all angle are 50,50,80

Answered by Brenquoler
321

Two angles of a triangle are equal and the third angle is greater than each of those angles by 30⁰. (Given)

Let x, x, x + 30⁰ be the angles of a triangle.

Sum of all angles in a triangle = 180⁰

x + x + x + 30⁰ = 180⁰8

3x + 30⁰ = 180⁰

3x = 150⁰

or x = 50⁰

And x + 30⁰ = 50⁰ + 30⁰ = 80⁰

Answer:

Three angles are 50⁰, 50⁰ and 80⁰.

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