Question

two angles of a triangle are in the ratio 4:5 if the sum of these angles is equal to the third angle find the angles of the triangle

Answer 1

✴✴$\huge \boxed{HEY \: FRIENDS!!}$✴✴

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✴✴$\huge \underline{Here \: is \: your \: answer↓}$⬇⏬⤵

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▶⏩$\bf{Let \: the \: ratio \: be \: x. :- \: 4x \: and \: 5x.}$

▶⏩ A/Q.

$\boxed{angle1 + angle2 = angle3.}$

▶⏩We know that :-)
→ In triangle:-

▶⏩$\huge \bf \boxed{angle1 + angle2 + angle3 = 180°.}$

↪➡$\bf{=> 4x + 5x + ( 4x + 5x ) = 180°.}$

↪➡$\bf{=> 9x + 9x = 180°.}$

↪➡$\bf {=> 18x = 180°.}$

↪➡$\bf{ = > x = \frac{180°}{18} .}$

$\huge \bf{=> x = 10°.}$

↪➡ All the angles of triangle are :-)

↪➡$\huge \boxed{angle1 = 4x = 4 × 10° = 40°.}$

↪➡$\huge \boxed{angle2 = 5x = 5 × 10° = 50°.}$

↪➡$\huge \boxed{angle3 = ( 4x + 5x ) = ( 40° + 50° ) = 90°.}$

✅✅ Hence, all the angles of triangle are finded ✔✔.

✴✴$\huge \boxed{THANKS}$✴✴


☺☺☺$\huge \bf \underline{Hope \: it \: is \: helpful \: for \: you}$✌✌✌.

Answer 2

●LET'S THE RATION COEFFIECIENT = x

◢SO

●ANGLES ARE => 4x and 5x
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●ACCORDING TO GIVEN CONDITION :-

=> 3rd angle = 4x + 5x = 9x
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●WE KNOW THAT

๛Sum of the triangle are = 180

◢SO

=> 4x + 5x + 9x = 180

=> 18x = 180

=> x = 180/18

=> x = 10. _________[◢Eq(1)]
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◢HENCE,

●THE ANGLES OF TRIANGLE ARE

=> 4x, 5x and 9x

●PUT THE VALUE OF "x" FROM Eq(1)

=> 40, 50 and 90. ________________[◢ANSWER]

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______☆$BE \: \: \: \: BRAINLY$☆_______