Question

Two angles of a triangle are in the ratio of 2:3.If the sum of these two angles is 30° less than the third angle, find all the three angles of the triangle?

Answer 1

angle 1=x
angle 2=y
x+y=180-30
x+y=150

let ratio constant be t
therefore

2t+3t=150
therefore
5t=150 and
t=150/5
t=30 degrees

therefore 2t equals 2 x 30 =60 degress
3t= 3 x 30= 90 degrees

check
x+y=150
60+90= 150

Answer 2

from question


third angle = 2x + 3x + 30


now sum of all angle is 180

therefore,
2x + 3x + 2x + 3x + 30 = 180 degrees
So,. 10x = 150
therefore x = 15


therefore
first angle = 2x = 2 × 15 = 30 degree
aecond angle = 3x = 3 × 15 = 45 degree
first angle = 2x + 3x + 30 = 30 + 45 + 30 = 105 degree