Question

two angles of hexagon are 120and 160 if the remaining four angles are equal find each equal angle

Answer 1

Given-
Two angles of hexagon are 120and 160

No. of  sides of hexagon = 6


As we know that

Sum of interier angles of any polygon = (n - 2) × 180° where n= no. of sides

Hence total sum of interier angles in Hexagon = (6-2)× 180° = 4*× 180°= 720°

Now, since two angle is given- so,  suppose each remaining eqal side angle = x

120+160+4x= 720°

=> 4x= 720°- 280°

Hence, x= 440°/4 = 110°

Hence, x= 110°


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Answer 2

Answer:

110°

Step-by-step explanation:

Given- two angels are 120 , 160

So , 120 + 160 = 280

and other 4 angels are equal

let n be 6 because of it six side

Use the formula ( 2n - 4 ) × 90°

=> ( 2× 6 - 4 ) × 90° = 280°

= > ( 12 - 4 ) × 90° = 280°

=> 8 × 90° = 280°

=> 720° - 280° = 110°