Question

Two angles of polygon are right ange and remaining angle is 160°. Find the sides

Answer 1

Question :

Two angles of polygon are right angle and remaining angle is 160°. Find the sides.

$\textbf {\underline {\underline {Step-By-Step\:Explanation:-}}}$

$\textbf {\underline {Given:}}$

• Two angles of polygon are right angle
• Remaining angle = 160°

$\textbf {\underline {To\:Find:}}$

• Sides of the polygon.

$\huge\underline\green {\tt Solution:}$

Let the unknown sides be ' P '

➡ Sum of all angles of polygon = 180° ( n - 2 )

Now,

Sum of angle = 2 × 90° + ( n - 2 ) × 160°

= 180° + 160n - 320°

Now,

180° ( n - 2 ) = 180° + 160n - 320°

➡ 180n - 360° = 180° - 320° + 160n

➡ 180n - 160n = 180° - 320° + 360°

➡ 20n = 220°

➡ n = $\dfrac {220}{20}$

•°• n = 11

This polygon is hendecagon.

Answer :

Sides of the given polynomial are 11. Hence, it is a hendecagon.