Question

Two angles of Triangle are equal and the third angle is grater than each one of them by 18°.Find the angles.​

Answer 1

Consider ∠A and ∠B in a triangle is x

∘

We know that the sum of all the angles in a triangle is 180

∘

.

So we can write it as

∠A+∠B+∠C=180

∘

By substituting the values

x

∘

+x

∘

+∠C=180

∘

By addition

2x

∘

+∠C=180

∘

..(1)

According to the question we get

∠C=x

∘

+18

∘

.(2)

By substituting (2) in (1) we get

2x

∘

+x

∘

+18

∘

=180

∘

On further calculation

3x

∘

+18

∘

=180

∘

By subtraction

3x

∘

=180

∘

−18

∘

3x

∘

=162

∘

By division

x

∘

=162/3

x

∘

=54

∘

By substituting the values of x

∠A=∠B=54

∘

∠C=54

∘

+18

∘

=72

∘

Therefore, ∠A=54

∘

,∠B=54

∘

and ∠C=72

∘

Answer 2

Answer:

the answer is 54, 54, and 72

Step-by-step explanation:

let the angle be A

A+A+A+18=180

3A+18=180

3A=180-18

3A=162

A=162/3

A=54

so, angle1=54

angle2=54 and

angle3=54+18=72