Question

two angles of triangles are equal and the third angle is greater than each of these angle by 30° find all the angles of the triangle

Answer 1

heya


let the two equal angles bex
and third angle Bex+30
sum of all the angles of a triangle is 180
x+x+x+30=180°
3x+30°=180°
3x=180°-30°
3x=150°
x=150°/3
x=50°

first angle is 50°
second angle is 50°
third angle is 50+30=80°