Two aps have same common difference the first term of an of this is 8 and the other is the difference between their 30th thomas
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Answer:
a₁ - a₂
Step-by-step explanation:
SInce all values are not present, i am unable to answer correctly. But if my guess is right, the first term of second AP is given as well.
We know that tₙ a + (n-1)d .
Irrespective of difference between which terms we require, the difference will always be difference between first terms.
for example, let a₁ be the first term for first AP and common diff is d₁.
Let a₂ be the first term for second AP and common diff is d₂.
given, common diff is same i.e. d₁ = d₂.
t₃₀ of first AP = a₁ + (30 - 1)d₁
t₃₀ of 2nd AP = a₂+ (30 - 1)d₂
Difference in their 30th term = a₁ + 29d₁ - a₂ - 29d₂
= a₁ - a₂ (∵ d₁ = d₂)
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