Question

Two aps have same common difference the first term of an of this is 8 and the other is the difference between their 30th thomas

Answer 1

Answer:

a₁ - a₂

Step-by-step explanation:

SInce all values are not present, i am unable to answer correctly. But if my guess is right, the first term of second AP is given as well.

We know that tₙ  a + (n-1)d .

Irrespective of difference between which terms we require, the difference will always be difference between first terms.

for example, let a₁ be the first term for first AP and common diff is d₁.

                     Let a₂ be the first term for second AP and common diff is d₂.

                     given, common diff is same i.e. d₁ = d₂.

t₃₀ of first AP = a₁ + (30 - 1)d₁

t₃₀ of 2nd AP = a₂+ (30 - 1)d₂

Difference in their 30th term =   a₁ + 29d₁  - a₂ - 29d₂

                                                 = a₁ - a₂  (∵ d₁ = d₂)