Math, asked by prasadshiva1645, 5 hours ago

Two arithmetic progressions has the same common difference. If the first term of the first progression is 3 and that of the other is 8, then the difference between their 3rd term is

Answers

Answered by Anonymous
1

Step-by-step explanation:

Let the same common difference of two AP’s isd, Given that, the first term of first AP and second AP are 2 and 7 respectively, then the AP’s are

2,2 + d,2 + 2d,2 + 3d,.,.

and 7,7+ d, 7 +2d, 7+3d,…

Now, 10th terms of first and second AP’s are 2 + 9d and 7 + 9 d, respectively.

So, their difference is 7 + 9d – (2 + 9d) = 5

Also, 21st terms of first and second AP’s are 2 + 20d and 7 + 20d, respectively.

So, their difference is 7 + 20d – (2 + 9d) = 5

Also, if the a„ and bn are the nth terms of first and second AP.

Then, bn -an = [7 + (n-1)d)] – [2 + (n-1)d] = 5

Hence, the difference between any two corresponding terms of such AP’s is the same as the difference between their first terms.

Answered by swarajyakalbande14
1

Answer:

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