Question

Two articles were sold at same price .if the vendor had sold the first article at a profit of 20% the at what percent loss the vendor would have sold the second article if the sum of the cost price and selling price of both articles are same

Answer 1

Answer:

say cp=100 and sp=120

so profit% is 20%

Step-by-step explanation:

Now because sum of sp and cp remains same for both articles, sp100+cp120

=220

so loss=20

and loss%=(20/120)*100

=100/6

=16.66% ANSWER

Answer 2

He should sell the second article in the loss of 20%.

Step-by-step explanation:

Let x be the cost price of each article,

In first article,

There is a profit of 20%,

So, selling price of the article = (100+20)% of x

= 120% of x

$=\frac{120x}{100}$

= 1.2x,

Suppose there is loss of y% in the second article,

The its selling price = (100-y)% of x

According to the question,

Sum of cost prices = Sum of selling prices

x + x = 1.2x + (100-y)% of x

2x = 1.2x + (100-y)% of x

$2 = 1.2+ \frac{100-y}{100}$

$2 - 1.2 = \frac{100-y}{100}$

$0.8 = \frac{100-y}{100}$

$80=100-y$

$\implies y = 100 - 80 = 20\%$

Hence, he should sell the second article in the loss of 20%.

#Learn more:

By selling 60 articles a vendor gains the selling price of 15 articles.find his gain percentage

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