Two bags each contain white balls and green balls. Bag one contains 4 white balls and 3 green balls. Bag two contains 2 white balls and 4 green balls. A ball is drawn from each bag. What is the probability that both balls are green?
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Answered by
5
Answer:
prob = 2/7
Step-by-step explanation:
Here the drawing of a ball each from the two bags are two independent events.
Bag1: 4W + 3G Bag2: 2 W + 4 G
Probability that a ball drawn from bag1 is Green = 3/(4+3) = 3/7
Probability that a ball drawn from bag2 is Green = 4/(2+4) = 4/6 = 2/3
Hence the probability that both drawn balls are green = 3/7 * 2/3 = 2/7
Answered by
3
Answer:
Step-by-step explanation:
Here the drawing of a ball each from the two bags are two independent events.
Bag1: 4W + 3G Bag2: 2 W + 4 G
Probability that a ball drawn from bag1 is Green = 3/(4+3) = 3/7
Probability that a ball drawn from bag2 is Green = 4/(2+4) = 4/6 = 2/3
Hence the probability that both drawn balls are green = 3/7 * 2/3 = 2/7
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