Math, asked by billingsc26, 6 hours ago

two bags each hold 50 grams of sugar. After using 3 times as much sugar from bag one as from bag two, bag one has half as much sugar as bag two. How much sugar is in each bag now?

Answers

Answered by 8202sreejiths
0

Answer:

According to what I can see,  your equation should look like this:

 

50 - 3x = 1/2 (50-x)

Multiply both sides by 2 (to eliminate the 1/2

 

100-6x= 50-x

Add 6x to both sides

100= 50-5x

Subtract 50 from both sides

50=5x

Lastly, divide by 5

10=x

 

So, 10 kg of sugar was removed from bag 2.

 

3x= 30, so 30 kg of sugar was removed from bag 1.

 

50-30=20 kg remaining in bag 1.

50-10=40 kg remaining in bag 2.

Step-by-step explanation:

According to what I can see,  your equation should look like this:

 

50 - 3x = 1/2 (50-x)

Multiply both sides by 2 (to eliminate the 1/2

 

100-6x= 50-x

Add 6x to both sides

100= 50-5x

Subtract 50 from both sides

50=5x

Lastly, divide by 5

10=x

 

So, 10 kg of sugar was removed from bag 2.

 

3x= 30, so 30 kg of sugar was removed from bag 1.

 

50-30=20 kg remaining in bag 1.

50-10=40 kg remaining in bag 2.

Answered by fatimaamumtaz123
0

Answer:



Step-by-step explanation:

According to what I can see,  your equation should look like this:

 

50 - 3x = 1/2 (50-x)

Multiply both sides by 2 (to eliminate the 1/2

 

100-6x= 50-x

Add 6x to both sides

100= 50-5x

Subtract 50 from both sides

50=5x

Lastly, divide by 5

10=x

 

So, 10 kg of sugar was removed from bag 2.

 

3x= 30, so 30 kg of sugar was removed from bag 1.

 

50-30=20 kg remaining in bag 1.

50-10=40 kg remaining in bag 2.

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