Question

two bags together contained 50 chocolates. From the first bag, 12 chocolates were given to a child. Then 8 chcolates were taken from the first bag and put into the second bag to make the number of chcolates equal in both bags. How many chcolates were orginally there in each bag?

Answer 1

remove 12from 50 because he given it to child
$50 - 12 = 38$
divide it by 2
$38 \div 2 = 19$
add 8 to it
$19 + 8 = 27$
he told eight from first are transfer to second
$27 - 8 = 19$
$11 + 8 = 19$
Both side equal chocolates are there. first bag 39 , second bag 11.