Question

Two balls A and B are thrown with speeds u and u/2 respectively. Both the
n with speeds u and u/2 respectively. Both the balls cover the same
horizontal distance before returning to the plane of projection. If the angle os
ung to the plane of projection. If the angle of projection of ball B
is 15º with the horizontal, then the angle of projection of A is:-
​

Answer 1

Explanation:

The time consumed for  an object to be projected and landing is called the time of flight.

●This depends on the initial velocity  and the angle of projection of the projectile.

When the projectile attains  a vertical velocity of zero, this is the maximum height attended by it.

●The horizontal displacement of the projectile is termed as range of the projectile,

●Solution: R=u2sin2θ/g:

As per problem,

(u/2 )2sin 300/g =u2sin2θ/g:

Therefore, u2sin300/4g=u2sin2θ /g

or, u2/8g= u2sin2θ /g

or, sin2θ =1/8 or,

2θ=sin-1(1/8)    

or, θ=1/2 sin-1(1/8)

Angle of projection of  A:  is 1/2sin-1(1/8)  .

hope it will help you dear☺☺☺☺.....