Question

Two balls A and B have masses m and 2m and velocities v and 2v respectively. What is the ratio of momentum A to that of B​

Answer 1

$\huge \sf \pink{P=mv}\ \; \bigstar$

where ,

• P denotes momentum
• m denotes mass
• v denotes velocity

Explanation :

Mass A = m

Mass B = 2m

Velocity A = v

Velocity B = 2v

$\to \sf \dfrac{P_A}{P_B}=\dfrac{m_A.v_A}{m_B.v_B}\\\\\to \sf \dfrac{P_A}{P_B}=\dfrac{(m)(v)}{(2m)(2v)}\\\\\to \sf \dfrac{P_A}{P_B}=\dfrac{mv}{4mv}\\\\\leadsto \sf \green{\dfrac{P_A}{P_B}=\dfrac{1}{4}}\ \; \bigstar$

More Info :

Relation b/w pressure , Force and area is given by ,

$\sf Pressure =\dfrac{Force}{Area}\ \; \bigstar$

Relation b/w density , mass and volume is given by ,

$\sf Density=\dfrac{Mass}{Volume}\ \; \bigstar$

Answer 2

Answer:

\huge \sf \pink{P=mv}\ \; \bigstarP=mv ★

where ,

P denotes momentum

m denotes mass

v denotes velocity

Explanation :

Mass A = m

Mass B = 2m

Velocity A = v

Velocity B = 2v

\begin{gathered}\to \sf \dfrac{P_A}{P_B}=\dfrac{m_A.v_A}{m_B.v_B}\\\\\to \sf \dfrac{P_A}{P_B}=\dfrac{(m)(v)}{(2m)(2v)}\\\\\to \sf \dfrac{P_A}{P_B}=\dfrac{mv}{4mv}\\\\\leadsto \sf \green{\dfrac{P_A}{P_B}=\dfrac{1}{4}}\ \; \bigstar\end{gathered}

→

P

B

P

A

=

m

B

.v

B

m

A

.v

A

→

P

B

P

A

=

(2m)(2v)

(m)(v)

→

P

B

P

A

=

4mv

mv

⇝

P

B

P

A

=

4

1

★

More Info :

Relation b/w pressure , Force and area is given by ,

\sf Pressure =\dfrac{Force}{Area}\ \; \bigstarPressure=

Area

Force

★

Relation b/w density , mass and volume is given by ,

\sf Density=\dfrac{Mass}{Volume}\ \; \bigstarDensity=

Volume

Mass

★