Two balls A and B of masses 100 grams and 300 grams respectively are pushed horizontally from a table of height 3 meters. Ball has is pushed so that its initial velocity is 10 m/s and ball B is pushed so that its initial velocity is 15 m/s.
a) Find the time it takes each ball to hit the ground.
b) What is the difference in the distance between the points of impact of the two balls on the ground?
Answers
Answer:
a) The two balls are subject to the same gravitational acceleration and therefor will hit the ground at the same time t found by solving the equation
-3 = -(1/2) g t2
t = √ (3(2)/9.8) = 0.78 s
b) Horizontal distance XA of ball A
XA = 10 m/s * 0.78 s = 7.8 m
Horizontal distance XB of ball B
XB = 15 m/s * 0.78 s = 11.7 m
Difference in distance XA and XB is given by
|XB - XA| = |11.7 - 7.8| = 3.9 m
Explanation:
Answer:
a) The two balls are subject to the same gravitational acceleration and therefor will hit the ground at the same time t found by solving the equation
-3 = -(1/2) g t2
t = √ (3(2)/9.8) = 0.78 s
b) Horizontal distance XA of ball A
XA = 10 m/s * 0.78 s = 7.8 m
Horizontal distance XB of ball B
XB = 15 m/s * 0.78 s = 11.7 m
Difference in distance XA and XB is given by
|XB - XA| = |11.7 - 7.8| = 3.9 m
Explanation: