Two balls A and B of masses 40 g and 50 g are moving at speeds of 40
m's and 30 m/s respectively. If after colliding, B stars moving with a
velocity of 25 m/s, what is the velocity of A?
Answers
Explanation:
Case of A
mass=40 g= 40/1000 0.04kg
velocity=40m/second
Case of B
mass=60 g = 60/1000= 0.06kg
velocity=30m/second
Let whole it be a system and before collision it will be called as initial momentum and after collision it will be called as final momentum
Initial system
momentum of A and B before collision
Initial momentum= Momentum of A before collision + Momentum of B before collision
Momentum =mass * velocity
Initial momentum= 0.04*40 + 0.06*30= 1.6+1.8= 3.4kg m/second
Final momentum= (0.04v)+(0.06 * 25) = 0.04v+1.5 kg m/second
According to law of conservation of momentum
Initial momentum = Final momentum
3.4 kg m/second =0.04v+ 1.5 kg m/ second
3.4 - 1.5 = 0.04v
1.9= 0.04v
1.9/ 0.04 = v
47.5 = v
Therefore, velocity of A will be 47.5 m / second
PLEASE MARK ME AS BRAINLIST