Question

Two balls A and B of same masses are thrown from the top of the building. A, thrown upward with velocity V and B, thrown downward with velocity V, then ​

Answer 1

Explanation:

The ball A after attaining maximum height reaches the point of projection with same velocity u and strikes the ground with same velocity v like ball B. Thus ,

ν

2

=u

2

+2gh⇒ν=

u

2

+2gh

So for both the cases velocity will be equal.

Answer 2

Answer:

The ball A after attaining maximum height reaches the point of projection with same velocity u and strikes the ground with same velocity v like ball B. Thus ,

v² = u² + 2gh = v = √u² + 2gh

So for both the cases velocity will be equal.