Question

Two balls are 8.0 metres apart and moving directly towards each other. If the first ball is moving at a speed of 2.5 ms–1 with respect to the ground and the second ball 3.5 ms–1 with respect to the ground, where will they collide?

Answer 1

Here, Relative velocity of ball with each other = 2.5+3.5 = 6m/s

Now, t = 8/6 = 1.34 sec.

Distance from 1st ball = 1.34 × 2.5 = 3.35 m

& Distance from 2nd ball = 8 - 3.35 m = 4.65m

Answer 2

The point of collision from first ball is 3.33 meters and 4.67 meters from the second ball.

GIVEN

Two balls are 8.0 metres apart and moving directly towards each other. If the first ball is moving at a speed of 2.5 ms–1 with respect to the ground and the second ball 3.5 ms–1 with respect to the ground.

TO FIND

Where will they collide?

SOLUTION

We can simply solve the above problem as follows;

Distance between the balls = 8 meters

Velocity of first ball(v1) = 2.5 m/s

Velocity of second ball (v2) = 3.5 m/s

Distance covered by the first ball (s1) = v1t

Distance covered by the second ball (s2) = v2t

Total distance (s) = s1 + s2

s = v1t + v2t

t = s /v1+v2

t = 8/6 = 1.33 seconds

s1 = 2.5 × 1.33 = 3.33 .meters

s2 = 8-3.33 = 4.67 meters

Hence, The point of collision from first ball is 3.33 meters and 4.67 meters from the second ball.

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