Question

Two balls are drawn at random from a bag containing 2 white, 3 red, 5 green and 4 black
balls, one by one without, replacement. Find the probability that both the balls are of
different colours.

Pls answer asap

Answer 1

Step-by-step explanation:

Assume only 2 balls are drawn one by one, the following analysis applies

combination of 2 balls drawn from among

14=

(12!)(2!)

14!

=

12!×2×1

14×13×12!

=9!

combination of 4 colours 2 at a time =

2!×2!

4!

=

2!×2×1

4×2×2!

=6

which are WR,WB,RG,RB and GB

combination of 1 W and 1 R=

1!×1

2×3

=6

combination of 1 W and 1 G=

1!.1!

2×5

=10

combination of 1 W and 1 B=2×4=8

combination of 1 R and 1 G=3×5=15

combination of 1 R and 1 B=3×4=12

combination of 1 G and 1 B=5×4=20

Total of such combinations =71

∴ probability of drawing atleast 2 balls of the same colour =

91

91−71

probabiliyt of atleast one of the above combination accuring =

91

71

=0.780219

I hope it will help you plz follow me and Mark as brain and like my answer