Question

Two balls are drawn from a bag containing 5 white and 7 black balls at random. What is the probability that they would be of different colours​

Answer 1

p(of different colors)=2!p(WB)

=2×5/12×7/11

70/132

I hope it is correct

Answer 2

The probability that they would be of different colors​ is $\frac{35}{132}$.

Step-by-step explanation:

Given : Two balls are drawn from a bag containing 5 white and 7 black balls at random.

To find : What is the probability that they would be of different colors​ ?

Solution :

A bag containing 5 white and 7 black balls.

Total number of balls = 5+7=12

Taking two cases :

Case 1 - When the first ball is white and the second black

The probability that the first ball is white is $\frac{5}{12}$.

The probability that the second ball is black is $\frac{7}{11}$.

The probability that the first ball is white and the second black is

$\frac{5}{12}\times \frac{7}{11}=\frac{35}{132}$

Case 2 - When the first ball is black and the second white.

The probability that the first ball is black is $\frac{7}{12}$.

The probability that the second ball is white is $\frac{5}{11}$.

The probability that the first ball is white and the second black is

$\frac{7}{12}\times \frac{5}{11}=\frac{35}{132}$

Therefore,  the probability that they would be of different colors​ is $\frac{35}{132}$.

#Learn more

A bag contains 5black, 7red, and 3white balls a ball is drawn from the bag at random find the probability that the ball drawn is black orwhite, not black

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