Question

A projectile is given an initial velocity of (3i+4j) . The equation of trajectory will be.

Answer 1

Answer:

The equation of motion: y=xtan(θ) - gx²/(2u²cos²(θ)) where u= the initial velocity and θ = the angle of projection. y = 4x/3 - 9.81x²/18 assuming g = 9.81 m/s².