Two balls are dropped from the same height from places A and B. The body at B takes two seconds
less to reach the ground at B and strikes the ground with a velocity greater than at A by 10 m/s. The
product of the acceleration due to gravity at the two places A and B is
1) 5
2) 25
3) 125
4) 12.5
Answers
Answered by
17
Answer:
....25 is the right answer.......
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Explanation:
Given, V
A
+10=V
B
V
A
−V
B
=−10
V
B
−V
A
=10⟶(1)
Similarly, t
A
−t
B
=2⟶(2)
(1)÷(2)
2
10
=
t
A
−t
B
V
B
−V
A
⇒5=
g
A
2h
−
g
B
2h
2g
B
h
−
2g
A
h
⇒5=
2h
(
g
A
1
−
g
B
1
)
2h
(
g
B
−
g
A
)
⇒5=
g
A
g
B
g
A
g
B
=25
So, product of acceleration of gravity of two place.A and B 125.
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