Question

Two balls are dropped to ground from different heights. One ball is dropped 2s after other but the first ball hits ground in 5s, then difference in their heights is​

Answer 1

$\underline{\underline{\mathfrak{\Large{Solution : }}}}\\ \\ \\ \sf \:Second\:ball\: hits\: the\: ground\:in\:(5 - 2) = 3s \\ \\ \\ \sf\:First\:ball\:hits\:ground\:in\:5s \\ \\ \\ \sf\:S = ut + \dfrac {1}{2} × a × t^{2} \\ \\ \\ \sf\:h_{1} = 0 + \dfrac {1}{2} × 10 × 5^{2} \\ \\ \\ \sf\:h_{2} = 0 + \dfrac {1}{2} × 10 × 3^{2} \\ \\ \\ \sf\:h_{1} - h_{2} = 5 (5^{2} - 3^{2}) = 80 m$

Answer 2

Answer: They hit the ground at the same time even though they're dropped from different heights

Explanation: