If sin0=4/5 then find cos0
Answers
Answered by
2
Hey
Here H stands for hypotenuse,A for adjacent side and O for opposite side.
SinO=4/5=O/H
By Pythagoras theorm,
H^2=O^2+A^2
=>A^2=H^2-O^2=5^2-4^2=25-16
=>A^2=9
=>A=3
Now,
CosO=A/H=3/5
Here H stands for hypotenuse,A for adjacent side and O for opposite side.
SinO=4/5=O/H
By Pythagoras theorm,
H^2=O^2+A^2
=>A^2=H^2-O^2=5^2-4^2=25-16
=>A^2=9
=>A=3
Now,
CosO=A/H=3/5
Answered by
0
Hey dude. This is the answer to your question.
(2✓3)/5.
Please mark me as brainliest.
Thank you for increasing my knowledge.
Bye
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