Question

Two balls are projected at different angles from the same place and with the same initial speed of 50 m/s. Both balls have the same range of 216 m. The difference in their times of flight is close to

Answer 1

if angle is given we can find the ratio or diff of the given .
ie, from R= ucosA × T
we can find range.....
so as here range is equal...
and u , the initial velocity is also equal.....so we can find t1 and t2 seperately....then T1 - T2 gives the answer

Answer 2

t1= 2usinx/g
t2=2usin(90-x)/g
t1/t2= sinx/cosx
t1/t2= tanx
now we just need to find x we can easily calculate difference so i am using formula
u^2sin2x/g= 216
u= 50
g=10
2500/10 sinx= 216
sin 2x= 216/250 = approximately equals to pi/3
2x= pi/3= x= pi/6
now
t1/t2= tanx
t1/t2 = 1/root3
t1root3=t2
now
t1 = 2usinx/g
t1 = 2u sin30/g
t1= 10  now
t2 = 1/roo3 oft1
t2 = 10/root3 = 6.4 approx
now t1-t2 = 10-6.6 = 3.6 approx
dude hope u got it ask ur doubt in comment box this question was asked in nest 2015 ;) but its solution is not available on internet i have solved this own have any doubt ask in comment box