Question

two balls are simultaneously projected horizontly in opposite direction with speed 3m/s and 4m/s from the top of a building which is 80m high the value of g =10m/s² ,distance between the two balls they hit the ground is dash​

Answer 1

Answer:

answer : 4m

explanation : Let’s solve with different method.

here it is clear that balls are thrown horizontally so, the path of balls are parabolic.

it is example of horizontal projectile. equation of path of horizontal projectile is y = gx²/2u²

where y denoted vertical distance e.g., height of ball from which it is thrown. x is horizontal distance, g is acceleration due to gravity and u is initial velocity of body.

horizontal distance covered by first ball , x = \sqrt{\frac{2u^2y}{g}}=\sqrt{\frac{2(2)^280}{10}}=8m

g

2u

2

y

=

10

2(2)

2

80

=8m

horizontal distance covered by 2nd ball, x’ = \sqrt{\frac{2u^2y}{g} } =\sqrt{\frac{2(3)^280}{10}}=12m

g

2u

2

y

=

10

2(3)

2

80

=12m

hence, The separation between the two balls when they hit the ground is (12m - 8m) = 4m