Question

two balls carrying changes of +3uC and
-3uC attract each other with a force F. If
a charge of +3uC is added to both the
force between the balls will be
a) F/2 b)F c) zero d) 2F​
plz answer fast

Answer 1

$\large{\underline{\underline{\mathfrak{Answer :}}}}$

Force between balls will be (c) zero

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$\underline{\underline{\mathfrak{Step-By-Step-Explanation :}}}$

Initially :

• 1st Charge (Q1) = +3μC
• 2nd Charge (Q2) = -3μC
• Force = F

Finally :

• 1st Charge (Q1') = +3μC + 3μC = 6μC
• 2nd Charge (Q2') = -3μC + 3μC = 0μC
• let distance between balls (d) = x

Use Coulomb's Law for Final charges :

$\large{\boxed{\boxed{\rm{F \: = \: k \dfrac{Q_1' Q_2'}{d^2}}}}} \\ \\ \rightarrow {\sf{F \: = \: k \dfrac{6 \mu C \: \times \: 0}{x^2}}} \\ \\ \rightarrow {\sf{F \: = \: 0}} \\ \\ {\underline{\sf{\therefore \: Force \: between \: balls \: is \: 0 \: N}}}$

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$\large ♡ \: \: {\underline{\underline{\mathfrak{Additional \: Information :}}}} \: \: ♡$

Characteristics of Electric Charge :

• It is a fundamental quantity.

• Produces electrical or Magnetic Field.

• It's S.I unit is Coulomb (C).

• Formula is Q = I × t.

• It is a scaler quantity.

Answer 2

Answer:

Given:

2 balls having +3 μC and -3 μC attract each other with force F. Now +3 μC charge is added to both the balls.

To find:

New force of attraction

Concept:

Electrostatic force depends on 2 aspects :

• Directly proportionally to product of charges.
• Inversely proportional to square of distance of separation.

Calculation:

k is also called Coulomb's constant. The value of this constant is 1/4πε .

$\huge{ \red{F = \frac{k(3)(3)}{ {r}^{2} } }}$

$\huge{ \red{ = > F = \frac{9k}{ {r}^{2} } }}$

Now , new charges will be :

$q1 = + 3 + 3 = + 6 \mu c$

$q2 = - 3 + 3 = 0 \: \mu c$

New force be F2 :

$\huge{ \red{F2 = \frac{k(6)(0)}{ {r}^{2} } }}$

$\huge{ \red{ = > F2 = 0 }}$

So the new force will be 0 N .

Final answer :

$\boxed{\huge{ \green{ \bold{F2 = 0 \: N }}}}$