Question

two balls carrying charges +8 microcoulomb and -5 microcoulomb attract each other with a force F if a charge -3 microcoulomb is added to both what will be the force between them?

Answer 1

Hey ...

We know :->
--> Electromagnetic force is directly proportional to the product of charge

Initial Product of charges = ( -5 )( 8 )
Final Product of charges = ( 8 - 3 )( -5 - 3 )
= ( 5 )( -8 )

Since there is no change in the product, ( assuming that the distance between the two charges wasn't affected by the addition ), the force between them will remain 'F' ✓✓

Answer 2

The force between them remains the same i.e., F.

Two ball carrying charges +8μC and -5μC attract each other with a force, F.

if a charge -3μC is added to both, We have to find the force between them.

Two ball carrying charges s +8μC and -5μC are separated with a distance r.

From Coulomb's law of electrostatic force,

$F=\frac{1}{4\pi\epsilon_0}\frac{(8\mu C)(5\mu C)}{r^2}\:\:....(1)$

Now -3μC is added to each charge.

∴ q₁ = +8μC + (-3μC) = +5μC

q₂ = -5μC + (-3μC) = -8μC

Now the electrostatic force applying Coulomb's law is given by,

$F'=\frac{1}{4\pi\epsilon_0}\frac{(5\mu C)(8\mu C)}{r^2}\:\:....(2)$

From equations (1) and (2), We get,

F = F'

Therefore the force between them will be the same. i.e., F.

Also read similar questions : two point charges of + 3 microcoulomb and + 4 microcoulomb repel each other with a force of 10 Newton if it is given an ...

https://brainly.in/question/8518544

two small identical spheres having charges 10 microcoulomb and - 90 microcoulomb attract each other with a force of F Ne...

https://brainly.in/question/3910890

#SPJ3