Question

two balls having mass 2kg and 3kg are approaching each other with velocities 3 m/s and 2 m/s respectively on the horizontal surface they undergo a head on elastic collision find out the maximum potential energy of deformation.

Answer 1

According to the law of conservation of momentum,

m1u1−m2u2=m1v1−m2v2

2×6−3×4=2×v1−3×3

12−12=2v1−9

2v1=9

v1=4.5

The velocity of the smaller ball after collision will me 4.5 m/s. But in the opposite direction of the first body.

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And now u can calculate potential energy