Two balls of different masses are thrown vertically upward with same initial velocity. Maximum heights attained by them are h1 and h2 respectively. What is h1/h2?
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The height reached is independent of the mass of the body. So h1/h2=1
You can see this for yourself using formula [tex] v^{2}-u^{2} =2gh [/tex]
v=0 at top. So when we rearrange we see that h depends on only initial velocity which is same here. Good luck :)
You can see this for yourself using formula [tex] v^{2}-u^{2} =2gh [/tex]
v=0 at top. So when we rearrange we see that h depends on only initial velocity which is same here. Good luck :)
sukhijasanya2:
thanks it helped a lot
Answered by
0
Explanation:
The height reached is independent of the mass of the body. So h1/h2=1
You can see this for yourself using formula v^{2}-u^{2} =2ghv
2
−u
2
=2gh
v=0 at top. So when we rearrange we see that h depends on only initial velocity which is same here. Good luck :)
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