Question

Two balls of masses 2 kg and 1 kg are dropped from same height what is the ratio of momentum when they just to hit the ground ( g = 10 ms-2)

Answer 1

Answer:

p1 : p2 = 2 : 1

Explanation:

Mass of ball 1 (m1) = 2kg

Mass of Ball 2 (m2) = 1kg.

Height of both the balls = equal = h.

Initial velocity of both the balls = 0.

Thus, Final velocity of ball 1 (V1) = √(2.g.h) = √(20h)

Final velocity of ball 2 (V2) = √(2.g.h) = √(20h)

Hence, Momentum of first ball (p1) = m.V1 = 2√(20h)

Momentum of second ball (p2) = m.V2 = √(20h)

Therefore,

Ratio of their momentum = p1/p2 = 2√[20h/20h]

= 2/1

Thus,

Ratio of their momentum = p1 : p2 = 2 : 1.

Answer 2

Explanation:

take height as x

and

accelerated motion formula:v²=u²+2as