Question

Two bar magnets of length 0.1m and pole strength 75 Am each are placed on the same line.The distance between their centres is .2m.What is the resultant force due to one on the other when
(1)the north pole of one faces the south pole of the other
(2)the north pole of one faces the north pole of the other

Answer 1

Explanation:

Given Two bar magnets of length 0.1 m and pole strength 75 Am each are placed on the same line.The distance between their centres is .2 m.What is the resultant force due to one on the other when

(1)the north pole of one faces the south pole of the other

 (2)the north pole of one faces the north pole of the other

• Given pole strength m = 75 Am
• Now north pole of one magnet attracts the south pole of other magnet.
• Now F1 = μo / 4π x m^2 / r^2  
•              = 10^-7 x (75)^2 / (0.1)^2
•            = 562500 x 10^-7 (for attraction)
• Now when the north pole of magnet pulls north pole of other magnet
• So F2 = μ / 4π x m^2 /r^2
•          = 10^-7 x (75)^2 / (0.2)^2
•          = 140625 x 10^-7  
• Now south of magnet repels south of other magnet.
• So F3 = μo / 4π x m^2 / r^2
•          = 10^-7 x (75)^2 / (0.2)^2
•            = 140625 x 10^-7
• South of magnet attracts the north of magnet
• So F4 = μo / 4π x m^2 /r^2
•          = 10^-7 x (75)^2 / (0.3)^2
•         = 62500 x 10^-7
• Therefore net force of the magnet will be  
•  F1 + F4 – F2 – F3
• 562500 + 62500 – 140625 – 140625) x 10^-7
•  343750 x 10^-7
•         = 3.4 x 10^-2 N
• Therefore for attraction it will be 3.4 x 10^-2 N and also for repulsion it will be 3.4 x 10^-2 N

Reference link will be

https://brainly.in/question/87468

Answer 2

Answer:

upper one is correct answer is