Two bars a and B are equal length by b has an area of of the top of a and b as young modulus double that of B when yellow is applied to the 2 bars the ratio of deformation between a and b is
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Answer:
Correct option is
A
16
Using
Y=
△L/L
F/A
Y=
△L
1
/L
1
F/△
1
−(1)For bar A
Y=
△L
2
/L
2
F/△
2
−(2)For bar B
Volume is same for A and B
So,R(
2
d
1
)
2
L
1
=R(
2
d
2
)
2
L
2
d
1
2
L
1
=4d
1
2
L
2
(givend
1
=
2
1
d
2
)
L
2
L
1
=4
Dividing 1 and 2
1=
L
2
△L
1
A
1
L
1
△L
2
A
2
△L
2
△L
1
=4×4(∵
A
1
A
2
=(
d
1
d
2
)
2
=4)
△L
2
△L
1
=16
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