Two beaker of water A and B , initially are at the same temperature.The temperature of the water in beaker A is increased by 10°F and the temperature of water in beaker B is increased 10 K. After these temperature change,which beaker of water has the higher temperature?
Answers
Answer:
beaker b is hotter than beaker A b= -20℃
Explanation:
both waters =x
+10f to one beaker
+10k to another beaker
=x+10f
=x+10k
we can convert both to Celsius
f=temp-30
℃=10-30
= -20℃
let's we convert Kelvin
°c=0℃=temprature(273.15°k)
+°K
0℃+10°k=10℃
The solution to the above question is given below.
Let consider the initial temperature of both beakers to be X⁰ C
Beaker A of water having temperature increased by 10⁰F.
Converting 10⁰F to celsius = -12.222⁰C
So, the final temperature of beaker A = X+ (-12.222⁰C)
= X-12.22 ⁰C
Beaker B of water having temperature increased by 10K
Converting 10K into celsius = -263.15⁰C
So, the final temperature of beaker B = X+(-263.15⁰C)
= X-263.15 ⁰C
Therefore, beaker A of water has a higher temperature.