Question

two bills of $6075 and $8505 respectively are to be paid by the cheques of the same amount. what will be the largest possible amount of cheques?



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Answer 1

Answer:

Largest possible amount of cheque will be the HCF(6075,8505). . Applying Euclid's division lemma to 8505 and 6075, we have, 8505=6075×1+2430

since, remainder 2430eq0 again applying division lemma to 6075 and 2430 6075=2430×2+1215

Again remainder 1215eq0 So, again applying the division lemma to 2430 and 1215 2430=1215×2+0

Here the remainder is zero So, H.C.F =1215 Therefore, the largest possible amount of each cheque will be 1215 .

Answer 2

$\huge\mathfrak\blue{answer}$

=6075÷8805

=2430 answer

6075÷2430=1215

1215÷2430=1

hence,

A largest possible amount of each cheque 1215.