Question

two blocks A and B of masses 2kg and 5 kg respectively moving in opposite direction collide head on the velocity of a and b just before collision is 10 metre per second and 2 metre per second respectively what is their velocity if they stick there after collision?​

Answer 1

Answer:

.......................

Answer 2

Answer:

Answer:

5m/s is the required answer.

Explanation:

Given:-

Mass (m₁) = 3kg

Mass (m₁) = 2kg

Initial velocity, (u₁) = 15m/s

Initial velocity ,(u₂) = -10m/s (opposite in direction)

To Find :-

Combined velocity

Solution :-

Let the combined velocity of the sphere be v m/s.

Combined mass of the body after collision = m₁ + m₁

Combined mass of the body after collision = 3+2=5kg

Using conservation of momentum

• m₁u₁+m₂u₂ = m₁v₁+m₂v₂

Since after the collision the mass of sphere combined and also the velocity . So modified formula will be

➻ m₁u₁ + m₂u₂ = mv

Substitute the value we get

➻ 3×15 + 2×(-10) = 5 ×v

➻ 45 + (-20) = 5×v

➻ 45 -20 = 5×v

➻ 25 = 5×v

➻ 25/5 = v

➻ 5 = v

➻ v = 5m/s

Hence, the combined velocity of the sphere will be 5m/s .