Question

Two blocks A and B of masses 5 kg and 10 kg
respectively are pushed on rough surface. The
contact force between the blocks is (g = 10 m/s2)​

Answer 1

Answer:

use kinematic equations and you will get answer

Answer 2

Answer:60N

Explanation:

15×0.4×10

=60N

Net force =90-60

=30N

30 = m ×a

m = 15 =(10+5)

a= 2m/s²

For 10 kg block

=>N - 0.4×10×10 = 10×2

=>N= 60N