two blocks A and B of masses 8kg and today respectively on the horizontal frictionless surface as shown in the figure they are used by horizontally applied force of 50 Newton force exerted by b on a is
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Answer:
3 Newton
Explanation:
Let N be the normal applied between the block and by Newton's third law the force applied by B on A will be equal to force applied by A on B , that is equal to N
Acceleration of both blocks will be equal and taking whole as system acceleration is » 15/10
Writing equation according to the FBD ( Free Body Diagram ) :
On block A
→ 15 - N = 8a { a = 15/10 }
→ 15 - N = 8 * 15/10
→ N = 3 Newton
Verification by writing equation on block B
→ N = 2a { a = 15/10 }
→ N = 2 * 15/10
N = 3 Newton
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